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I suppose I've been gone long enough to permit one

Started by Ranpalan, September 14, 2011, 01:23:24 AM

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Ranpalan

Seeing the recent changes to AP, I decided that I like this place better after all.  So, hello all, I'll be a good deal more active here than I was the last months.

Oh wait, this site is awesome enough to require people to contribute, so I should probably say something about myself.

I first joined this site four or so years ago, and have been checking in occasionally since then.  Star and I have a history of disagreeing on things like file formats, but we don't hate each other (do we? :P).  I'm currently doing a double major in mathematics and computer science, and am greatly enjoying it -- I'm also rather busy, but mastrubation being part of an online community is important, so I'll be checking in regularly.

By the way, I also happen to program in C++ and Python, and am currently learning C# (although I'd have preferred Haskell or Ruby).  I've had plans for omorashi games, but haven't gotten anywhere with them so far;  however, it's not out of the question for me to help out if you happen to write in a language I know.

I quite enjoy chatting about all sorts of things -- does this site still have an IRC channel, and if so, is there any chance of bringing it to life?

Cheers,
Ran
Always happy to get PMs/IMs

Hamdiggity


packrat

Hey!  Long time no see.  I thought I recognized that avatar.  Glad to see you came back to us. 

That said, I gotta give you props for taking on a double major in Math and CompSci.  I tried CompSci on it's own and got my butt handed to me.  (And I've missed a year of school because of the ensuing tuition issues from failing those courses.)  But yeah, glad to see you've come back.  =)

Ranpalan

Hm?  What verifications?  What maths?  Me want!
Always happy to get PMs/IMs

FallenStar

I believe that's one of the verification questions users with less than 5 posts have to make in order to keep out spambots. Don't worry, it's a really easy math question. Anyone can answer it... I think.   :lol:
Welp... I'm fucked...

Sophie1618

Yeah... I didn't have to do this verifications after I got 5 posts ^^ But the Math verification is pretty easy. I had problems with the MC Chrono Trigger question because I was trying put 'Chrono' before see on the wikipedia that his name written 'Crono' >.<

Ranpalan

Ah, yes, if it's not harder than quadratic equations, everyone should be fine.
Always happy to get PMs/IMs

FallenStar

Coming up with easy to answer questions that everyone ought to know really taxes my poor brain.  :lol: 

I did change the Chrono Trigger question, though, so hopefully that won't be a problem anymore.
Welp... I'm fucked...

Ranpalan

If I may suggest, 0/0 (correct answer being 1 (very questionable) or undefined); sin(0) (correct answer being 1); sin^2(x) + cos^2(x) (correct answer being 1); e^(i*tau) where e is the base of the natural logarithm, i is the square root of minus one, and tau is the circumference of a circle divided by it's radius (correct answer being 1); and ln(e) (correct answer being 1).

:P
Always happy to get PMs/IMs

FallenStar

Are you some kind of fricking MATH genius?!  If I put 0/0, the most likely answer I'd get is 0.  People are incredibly stupid that way... particularly here in the U.S.   :lol:
Welp... I'm fucked...

Ranpalan

Hang on, that was stupid of me -- 0/0 should only be undefined, 0^0 can be 1 in some contexts.   :blushing:

And no, I'm not.
Always happy to get PMs/IMs

JackO

Nice to see you back here again Ranpalan  :clap:  I look forward to bumping into you around the forums.

Ultima02

Quote from: FallenStar on September 19, 2011, 03:35:12 PM
Are you some kind of fricking MATH genius?!  If I put 0/0, the most likely answer I'd get is 0.  People are incredibly stupid that way... particularly here in the U.S.   :lol:

Don't remind me.
I'd like to think that we americans are smarter than we're portrayed.
Autism is a difference

Autism is NOT a disability.

Mydnyght Edgeworth

Quote from: Ranpalan on September 19, 2011, 03:15:08 PM
e^(i*tau) where e is the base of the natural logarithm, i is the square root of minus one, and tau is the circumference of a circle divided by it's radius (correct answer being 1)

Wait, WHAT!?
e^((2pi)i) = 1!?!

Congrats. Mydnyght's mind is officially fucked HARDCORE.

This loli is not wearing any pants.
That renders your argument invalid.

Ranpalan

Mydnyght, I can explain, really!  (Although it'd be nice if Star installed LaTeX for that. ^^)

By the way, now that I've been banned from AP, expect me to hang around here even more.  Yay for bans!
Always happy to get PMs/IMs